先化简再求值:(x+3)/(x²-3x)-(x-1)/(x²-6x+9)除(x²-9)/x 其中x=2
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/02 03:28:25
![先化简再求值:(x+3)/(x²-3x)-(x-1)/(x²-6x+9)除(x²-9)/x 其中x=2](/uploads/image/z/10306761-33-1.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BC%EF%BC%9A%28x%2B3%29%2F%28x%26%23178%3B-3x%29-%28x-1%29%2F%28x%26%23178%3B-6x%2B9%29%E9%99%A4%EF%BC%88x%26%23178%3B-9%EF%BC%89%2Fx+%E5%85%B6%E4%B8%ADx%3D2)
先化简再求值:(x+3)/(x²-3x)-(x-1)/(x²-6x+9)除(x²-9)/x 其中x=2
先化简再求值:(x+3)/(x²-3x)-(x-1)/(x²-6x+9)除(x²-9)/x 其中x=2
先化简再求值:(x+3)/(x²-3x)-(x-1)/(x²-6x+9)除(x²-9)/x 其中x=2
(x+3)/(x²-3x)-(x-1)/(x²-6x+9)
----------------------------------
(x²-9)/x
是这个式子吗?
原式=x(x+3)(x-3)-(x-1)(x-3)(x-3)=(x-3)【(x²+3x)-(x²-4x+3)】
=(x-3)(7x-3)
当x=2时,原式=-1*11=-11