4a-9与3a-5互为相反数,则a²-2a+1=
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4a-9与3a-5互为相反数,则a²-2a+1=
4a-9与3a-5互为相反数,则a²-2a+1=
4a-9与3a-5互为相反数,则a²-2a+1=
a=2,答案是1
4a-9=-(3a-5)
a=2
a²-2a+1=1
1
1
4a - 9 与 3a - 5 互为相反数,则4a - 9 + 3a - 5 = 0,则7a = 14,a = 2
a² -2a + 1 = ( a - 1 )² = 1² = 1
希望我的回答对你有帮助,O(∩_∩)O~
4a-9=-3a+5
7a =14 a=2
则a²-2a+1=1
4a-9=-3a+5
算出来a,然后代进去
4a-9+3a-5=0
a=2
最后=1