解下列方程组 5x/2+y/5=-2 x/3+y/5=1/6 今晚 麻烦快点捏..[1] 5x/2+y/5=-2 x/3+y/5=1/6[2] x+1=5(y+2)3(2x-3y)=2(x-2y)+6[3] 2x+y 分之3=5x+2y分之4=1
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![解下列方程组 5x/2+y/5=-2 x/3+y/5=1/6 今晚 麻烦快点捏..[1] 5x/2+y/5=-2 x/3+y/5=1/6[2] x+1=5(y+2)3(2x-3y)=2(x-2y)+6[3] 2x+y 分之3=5x+2y分之4=1](/uploads/image/z/11651407-7-7.jpg?t=%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B%E7%BB%84+5x%2F2%2By%2F5%3D-2+x%2F3%2By%2F5%3D1%2F6+%E4%BB%8A%E6%99%9A+%E9%BA%BB%E7%83%A6%E5%BF%AB%E7%82%B9%E6%8D%8F..%5B1%5D+5x%2F2%2By%2F5%3D-2+x%2F3%2By%2F5%3D1%2F6%5B2%5D+x%2B1%3D5%28y%2B2%293%282x-3y%EF%BC%89%3D2%EF%BC%88x-2y%29%2B6%5B3%5D+2x%2By+%E5%88%86%E4%B9%8B3%3D5x%2B2y%E5%88%86%E4%B9%8B4%3D1)
解下列方程组 5x/2+y/5=-2 x/3+y/5=1/6 今晚 麻烦快点捏..[1] 5x/2+y/5=-2 x/3+y/5=1/6[2] x+1=5(y+2)3(2x-3y)=2(x-2y)+6[3] 2x+y 分之3=5x+2y分之4=1
解下列方程组 5x/2+y/5=-2 x/3+y/5=1/6 今晚 麻烦快点捏..
[1] 5x/2+y/5=-2
x/3+y/5=1/6
[2] x+1=5(y+2)
3(2x-3y)=2(x-2y)+6
[3] 2x+y 分之3=5x+2y分之4=1
解下列方程组 5x/2+y/5=-2 x/3+y/5=1/6 今晚 麻烦快点捏..[1] 5x/2+y/5=-2 x/3+y/5=1/6[2] x+1=5(y+2)3(2x-3y)=2(x-2y)+6[3] 2x+y 分之3=5x+2y分之4=1
5x/2+y/5=-2 (1)
x/3+y/5=1/6(2)
(1)式-(2)式得:5x/2-x/3=-13/ 6
解得x=-1
y=5/2
[2] x+1=5(y+2)(1)
3(2x-3y)=2(x-2y)+6(2)
(1)式变形得x-5y=9(3)
(2)式变形得4x-5y=6(4)
(3)式-(4)式得:-3x=3
解得x=-1
y=-2
[3] 2x+y 分之3=5x+2y分之4=1
变形得2x+y =3(1)
5x+2y=4(2)
2(1)式-(2)式得:x=-2
y=7
(1)x=-1 y=5/2
(2) x=-1 y=-2
(3) x=-2 y=7
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