设f(x)=1/[(2^x)+√2],则f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=?正确答案是3√2球过程提问如题,
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 12:32:48
![设f(x)=1/[(2^x)+√2],则f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=?正确答案是3√2球过程提问如题,](/uploads/image/z/12933434-2-4.jpg?t=%E8%AE%BEf%28x%29%3D1%2F%5B%282%5Ex%29%2B%E2%88%9A2%5D%2C%E5%88%99f%28-5%29%2Bf%28-4%29%2Bf%28-3%29%2B%E2%80%A6%2Bf%280%29%2Bf%281%29%2Bf%285%29%2Bf%286%29%3D%3F%E6%AD%A3%E7%A1%AE%E7%AD%94%E6%A1%88%E6%98%AF3%E2%88%9A2%E7%90%83%E8%BF%87%E7%A8%8B%E6%8F%90%E9%97%AE%E5%A6%82%E9%A2%98%2C)
设f(x)=1/[(2^x)+√2],则f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=?正确答案是3√2球过程提问如题,
设f(x)=1/[(2^x)+√2],则f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=?正确答案是3√2球过程
提问如题,
设f(x)=1/[(2^x)+√2],则f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=?正确答案是3√2球过程提问如题,
因为f(x)+f(1-x)
=1/[(2^x)+√2]+1/[(2^1-x)+√2]
=1/[(2^x)+√2]+2^x/[2+√2(2^x)]
=√2/[√2(2^x)+2]+2^x/[2+√2(2^x)]
=(√2+2^x)/[2+√2(2^x)]=1/√2=√2/2,
所以f(-5)+f(6)=√2/2
f(-4)+f(5)=√2/2
f(-3)+f(4)=√2/2,
f(-2)+f(3)=√2/2,
f(-1)+f(2)=√2/2,
f(0)+f(1)=√2/2,
所以f(-5)+f(-4)+f(-3)+…+f(0)+f(1)+f(5)+f(6)=3√2.
设f(x)+2f(1/x)=2x+1,则f(x)=
设2f(x)+f(1-x)=x^2,则f(x)=?
设f(x)=x(x-1)(x-2)...(x-999),则f'(0)=?
设f(x)=x(x-1)(x-2).(x-1000) 则f'(0)=?RT
设f(x)=x(x+1)(x+2).(x+100),则f '(0)=
高数题:设f(x)=x.(x+1).(x+2).(x+n),则f 3Q
设f(1/x)=x/1-x^2,则f(x)= ,f(√2-1)=如题
设函数f(x)满足f(x)+2f(1/x)=x,求f(x)
设函数f(x)满足f(x)+2f(1/x)=2x+1,则f(x)=
设f(x)满足3f(x)+2f(1/x)=4x,则f(x)=__.
设df(x)=x/√(1-x^2) 则f(x)=
设f(x)满足f(x)+2f(1/x)=3x,则f(x)的表达式是?
设f(x)=x/2+1/x(x
设f(x)=ln√x,x>=1,y=f(f(x))设f(x)=ln√x,x>=1, y=f(f(x)),求dy/dx|x=0 2x-1,x
设函数f(x)=1+f(1/x)log2 x,则f(2)=?
设f(x)=|x-1|-|x| 则f[f(1/2)]=
设f{f(x)}=2x-1,则一次函数f(x)=?
设2f(x)+f(1-x)=x2,则f(x)=