2X/x+3-12/(x²+4x+3)=1答案正确马上采纳,要过程,舍去的话也要写出来,谢谢
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2X/x+3-12/(x²+4x+3)=1答案正确马上采纳,要过程,舍去的话也要写出来,谢谢
2X/x+3-12/(x²+4x+3)=1
答案正确马上采纳,要过程,舍去的话也要写出来,谢谢
2X/x+3-12/(x²+4x+3)=1答案正确马上采纳,要过程,舍去的话也要写出来,谢谢
答:
2x/(x+3)-12/(x^2+4x+3)=1
2x(x+1) / [(x+1)(x+3)]-12/[(x+1)(x+3)]=1
所以:
2x^2+2x-12=x^2+4x+3
x^2-2x-15=0
(x-5)(x+3)=0
解得:x=5(x=-3不符合,分母不为0,舍弃)
经检验,x=5是原分式方程的根
[2x(x+1)-12-(x^2+4x+3)]/(x+3)(x+1)=0
2x^2+2x-12-x^2-4x-3
=x^2-2x-15
=(x+3)(x-5)=0
x=5(x不能等于-1或-3)。