满足(a-b)2+(b-a)•│a-b│=ab,(ab≠0)的有理数a和b,一定不满足的关系是( )(A)ab0 (C)a+b>0 (D)a+b
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/04 01:07:36
![满足(a-b)2+(b-a)•│a-b│=ab,(ab≠0)的有理数a和b,一定不满足的关系是( )(A)ab0 (C)a+b>0 (D)a+b](/uploads/image/z/14683296-48-6.jpg?t=%E6%BB%A1%E8%B6%B3%28a-b%292%2B%28b-a%29%26%238226%3B%E2%94%82a-b%E2%94%82%3Dab%2C%28ab%E2%89%A00%29%E7%9A%84%E6%9C%89%E7%90%86%E6%95%B0a%E5%92%8Cb%2C%E4%B8%80%E5%AE%9A%E4%B8%8D%E6%BB%A1%E8%B6%B3%E7%9A%84%E5%85%B3%E7%B3%BB%E6%98%AF%28+%29%28A%29ab0+%28C%29a%2Bb%3E0+%28D%29a%2Bb)
满足(a-b)2+(b-a)•│a-b│=ab,(ab≠0)的有理数a和b,一定不满足的关系是( )(A)ab0 (C)a+b>0 (D)a+b
满足(a-b)2+(b-a)•│a-b│=ab,(ab≠0)的有理数a和b,一定不满足的关系是( )
(A)ab0 (C)a+b>0 (D)a+b
满足(a-b)2+(b-a)•│a-b│=ab,(ab≠0)的有理数a和b,一定不满足的关系是( )(A)ab0 (C)a+b>0 (D)a+b
设a和b,满足题目条件,首先一定有a
(a-b)2+(b-a)•│a-b│只有两种情况:当b-a≥0时,原式=2(a-b)2;当b-a<0时,原式=0,二者都≥0,也即ab≥0,因此A项错。
c