无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p.求(m+P)^p-q的值
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![无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p.求(m+P)^p-q的值](/uploads/image/z/2083352-32-2.jpg?t=%E6%97%A0%E8%AE%BAX%E5%8F%96%E4%BD%95%E5%80%BC%2C%E5%A4%9A%E9%A1%B9%E5%BC%8F%28m-1%29x%5E3%2B2mx%5E2%2B%28m%2B1%29x%2Bp%3Dpx%5E2-qx%2Bp.%E6%B1%82%28m%2BP%29%5Ep-q%E7%9A%84%E5%80%BC)
无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p.求(m+P)^p-q的值
无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p.求(m+P)^p-q的值
无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p.求(m+P)^p-q的值
无论X取何值,多项式(m-1)x^3+2mx^2+(m+1)x+p=px^2-qx+p
(m-1)=0,2m=p,(m+1)=-q
m=1,p=2,q=2
(m+P)^p-q=(1+2)^2-2=7