a^2-1分之a-2除以(a-1-a+1分之2a-1),其中a是方程x^2-x=根号3的根
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![a^2-1分之a-2除以(a-1-a+1分之2a-1),其中a是方程x^2-x=根号3的根](/uploads/image/z/2682248-32-8.jpg?t=a%5E2-1%E5%88%86%E4%B9%8Ba-2%E9%99%A4%E4%BB%A5%28a-1-a%2B1%E5%88%86%E4%B9%8B2a-1%29%2C%E5%85%B6%E4%B8%ADa%E6%98%AF%E6%96%B9%E7%A8%8Bx%5E2-x%3D%E6%A0%B9%E5%8F%B73%E7%9A%84%E6%A0%B9)
a^2-1分之a-2除以(a-1-a+1分之2a-1),其中a是方程x^2-x=根号3的根
a^2-1分之a-2除以(a-1-a+1分之2a-1),其中a是方程x^2-x=根号3的根
a^2-1分之a-2除以(a-1-a+1分之2a-1),其中a是方程x^2-x=根号3的根
(a-2)/(a²-1) ÷ (a-1)-(2a-1/a+1)
=(a-2)/(a²-1) ÷ [(a+1)(a-1)-(2a-1)]/a+1)
=(a-2)/(a²-1) ÷ (a²-2a/a+1)
=[(a-2)/(a+1)(a-1)]x(a+1)/a(a-2)
=1/(a²-a)
a是方程x²-x=√3的根
所以a²-a=√3
所以原式=1/√3=√3/3
∵a是方程x^2-x=根号3的根
∴a²-a=√3
∴(a-2)/(a^2-1) ÷[a-1-(2a-1)/(a+1)]
=(a-2)/(a^2-1) ÷[(a²-1)/(a+1)-(2a-1)/(a+1)]
=(a-2)/(a^2-1) ÷[(a²-2a)/(a+1)]
=(a-2)/[(a-1)(a+1)]*(a+1)/[a...
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∵a是方程x^2-x=根号3的根
∴a²-a=√3
∴(a-2)/(a^2-1) ÷[a-1-(2a-1)/(a+1)]
=(a-2)/(a^2-1) ÷[(a²-1)/(a+1)-(2a-1)/(a+1)]
=(a-2)/(a^2-1) ÷[(a²-2a)/(a+1)]
=(a-2)/[(a-1)(a+1)]*(a+1)/[a(a-2)]
=1/[a(a-1)]
=1/(a²-a)
=1/√3
=√3/3
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化简以后等于1/(a^2-a)
又因为a是X^2-X=√3的解
则a^2-a=√3
所以1/(a^2-a)=1/√3=√3/3
=√3/3