设abc=1,化简 ab/(ab+b+1) +bc/(bc+c+1) +ca/(ca+a+1)
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![设abc=1,化简 ab/(ab+b+1) +bc/(bc+c+1) +ca/(ca+a+1)](/uploads/image/z/316648-64-8.jpg?t=%E8%AE%BEabc%3D1%2C%E5%8C%96%E7%AE%80+ab%2F%28ab%2Bb%2B1%29+%2Bbc%2F%28bc%2Bc%2B1%29+%2Bca%2F%28ca%2Ba%2B1%29)
设abc=1,化简 ab/(ab+b+1) +bc/(bc+c+1) +ca/(ca+a+1)
设abc=1,化简 ab/(ab+b+1) +bc/(bc+c+1) +ca/(ca+a+1)
设abc=1,化简 ab/(ab+b+1) +bc/(bc+c+1) +ca/(ca+a+1)
答案是1:把上式三部分标记为一,二,三.一=ab/(ab+b+abc)=a/a+1+ac.二=bc/(bc+c+abc)=b/(b+1+ab)=b/(b+abc+ab)=1/(1+ac+a).把化简后的一,二,三相加,分数线上下相等,=1