1.(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?3(a^3+a^2-a-1)-2(a^3-a)1(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?2 3(a^3+a^2-a-1)-2(a^3-a)\
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/06 15:58:56
![1.(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?3(a^3+a^2-a-1)-2(a^3-a)1(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?2 3(a^3+a^2-a-1)-2(a^3-a)\](/uploads/image/z/3172218-42-8.jpg?t=1.%EF%BC%882%EF%BC%8F3%EF%BC%89%5E2001%C3%97%EF%BC%881.5%EF%BC%89%5E2000%C3%B7%EF%BC%88%EF%B9%A31%EF%BC%89%5E2002%3D%3F%EF%BC%882%EF%BC%8F3%EF%BC%89%5E2001%C3%97%EF%BC%881.5%EF%BC%89%5E2000%C3%B7%EF%BC%88%EF%B9%A31%EF%BC%89%5E2002%3D%3F3%EF%BC%88a%5E3%EF%BC%8Ba%5E2-a-1%29-2%28a%5E3-a%291%EF%BC%882%EF%BC%8F3%EF%BC%89%5E2001%C3%97%EF%BC%881.5%EF%BC%89%5E2000%C3%B7%EF%BC%88%EF%B9%A31%EF%BC%89%5E2002%3D%EF%BC%9F2+3%28a%5E3%EF%BC%8Ba%5E2-a-1%29-2%28a%5E3-a%29%5C)
1.(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?3(a^3+a^2-a-1)-2(a^3-a)1(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?2 3(a^3+a^2-a-1)-2(a^3-a)\
1.(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?
(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?
3(a^3+a^2-a-1)-2(a^3-a)
1(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?
2 3(a^3+a^2-a-1)-2(a^3-a)\
1.(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?3(a^3+a^2-a-1)-2(a^3-a)1(2/3)^2001×(1.5)^2000÷(﹣1)^2002=?2 3(a^3+a^2-a-1)-2(a^3-a)\
(2/3)×(2/3)^2000×(1.5)^2000÷(﹣1)^2002
=(2/3)×(2/3×1.5)^2000÷1
=(2/3)×1
=2/3
(a^3+a^2-a-1)-2(a^3-a)
=a^3+a^2-a-1-2a^3+a
=-a^3+a^2-1