(1/2)已知数列an满足条件:a1=1.a2=r.(r>0)且{anan+1}是公比为q的等比数列,设bn=a2n-1+a2n,求数列bn的前
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![(1/2)已知数列an满足条件:a1=1.a2=r.(r>0)且{anan+1}是公比为q的等比数列,设bn=a2n-1+a2n,求数列bn的前](/uploads/image/z/3198334-22-4.jpg?t=%281%2F2%29%E5%B7%B2%E7%9F%A5%E6%95%B0%E5%88%97an%E6%BB%A1%E8%B6%B3%E6%9D%A1%E4%BB%B6%EF%BC%9Aa1%3D1.a2%3Dr.%28r%3E0%29%E4%B8%94%7Banan%2B1%7D%E6%98%AF%E5%85%AC%E6%AF%94%E4%B8%BAq%E7%9A%84%E7%AD%89%E6%AF%94%E6%95%B0%E5%88%97%2C%E8%AE%BEbn%3Da2n-1%2Ba2n%2C%E6%B1%82%E6%95%B0%E5%88%97bn%E7%9A%84%E5%89%8D)
(1/2)已知数列an满足条件:a1=1.a2=r.(r>0)且{anan+1}是公比为q的等比数列,设bn=a2n-1+a2n,求数列bn的前
(1/2)已知数列an满足条件:a1=1.a2=r.(r>0)且{anan+1}是公比为q的等比数列,设bn=a2n-1+a2n,求数列bn的前
(1/2)已知数列an满足条件:a1=1.a2=r.(r>0)且{anan+1}是公比为q的等比数列,设bn=a2n-1+a2n,求数列bn的前
an*an+1/an-1*an=q→an+1/an-1=q→an+2/an=q→a(2k+1)=a(2k-1)*q;a(2k)=a(2k-2)*q
a1=1,a2=r→bn=q^(n-1)+r*q^(n-1)→bn=(r+1)*q^(n-1)
∑bn=(r+1)*(q^0+q^1+q^2+...q^(n-1))=(r+1)*(1-q^n)/(1-q)
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