已知(b-1)²+a+2的绝对值=0求代数试3ab²-3a²+5a²b+b³-4ab²+8a²-5ba²-100b³的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 14:35:08
![已知(b-1)²+a+2的绝对值=0求代数试3ab²-3a²+5a²b+b³-4ab²+8a²-5ba²-100b³的值](/uploads/image/z/3810419-35-9.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%88b-1%29%26%23178%3B%2Ba%2B2%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D0%E6%B1%82%E4%BB%A3%E6%95%B0%E8%AF%953ab%26%23178%3B-3a%26%23178%3B%2B5a%26%23178%3Bb%2Bb%26%23179%3B-4ab%26%23178%3B%2B8a%26%23178%3B-5ba%26%23178%3B-100b%26%23179%3B%E7%9A%84%E5%80%BC)
已知(b-1)²+a+2的绝对值=0求代数试3ab²-3a²+5a²b+b³-4ab²+8a²-5ba²-100b³的值
已知(b-1)²+a+2的绝对值=0
求代数试3ab²-3a²+5a²b+b³-4ab²+8a²-5ba²-100b³的值
已知(b-1)²+a+2的绝对值=0求代数试3ab²-3a²+5a²b+b³-4ab²+8a²-5ba²-100b³的值
解
(b-1)²+/a+2/=0
∴b-1=0,a+2=0
∴b=1,a=-2
原式
=(3ab²-4ab²)+(-3a²+8a²)+(5a²b-5a²b)+(b³-100b³)
=-ab²+5a²-99b³
=2×1+5×4-99×1
=2+20-99
=-77