A={(x,y)|3x+2y=0},B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B,A∩C,A∩D
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![A={(x,y)|3x+2y=0},B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B,A∩C,A∩D](/uploads/image/z/4002351-15-1.jpg?t=A%3D%7B%28x%2Cy%29%EF%BD%9C3x%2B2y%3D0%7D%2CB%3D%7B%28x%2Cy%29%EF%BD%9Cx-y%3D2%7D%2CC%3D%7B%28x%2Cy%29%EF%BD%9C2x-2y%3D3%7D%2CD%3D%7B%28x%2Cy%29%EF%BD%9C6x%2B4y%3D2%7D%2C%E6%B1%82A%E2%88%A9B%2CA%E2%88%A9C%2CA%E2%88%A9D)
A={(x,y)|3x+2y=0},B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B,A∩C,A∩D
A={(x,y)|3x+2y=0},B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B,A∩C,A∩D
A={(x,y)|3x+2y=0},B={(x,y)|x-y=2},C={(x,y)|2x-2y=3},D={(x,y)|6x+4y=2},求A∩B,A∩C,A∩D
3x+2y=0
x-y=2
则5x=4,即x=4/5,代入x-y=2,y=4/5-2=-6/5
所以A∩B=(4/5,-6/5)
A∩C
3x+2y=0
2x-2y=3
则5x=3,即,x=3/5,代入2x-2y=3得:y=-9/10
A∩C=(3/5,-9/10)
A∩D
3x+2y=0
6x+4y=2
A∩D=空集,无解