1、分解因式(a²+b²)²-a²b²2、已知x=11/25,y=25/22,求(x+y)²-(x-y)²的值
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![1、分解因式(a²+b²)²-a²b²2、已知x=11/25,y=25/22,求(x+y)²-(x-y)²的值](/uploads/image/z/4316538-66-8.jpg?t=1%E3%80%81%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%28a%26%23178%3B%2Bb%26%23178%3B%29%26%23178%3B-a%26%23178%3Bb%26%23178%3B2%E3%80%81%E5%B7%B2%E7%9F%A5x%3D11%2F25%2Cy%3D25%2F22%2C%E6%B1%82%28x%2By%29%26%23178%3B-%28x-y%29%26%23178%3B%E7%9A%84%E5%80%BC)
1、分解因式(a²+b²)²-a²b²2、已知x=11/25,y=25/22,求(x+y)²-(x-y)²的值
1、分解因式(a²+b²)²-a²b²
2、已知x=11/25,y=25/22,求(x+y)²-(x-y)²的值
1、分解因式(a²+b²)²-a²b²2、已知x=11/25,y=25/22,求(x+y)²-(x-y)²的值
解1:
(a²+b²)²-a²b²
=(a²+b²)²-(ab)²
=(a²+b²+ab)(a²+b²-ab)
解2:
(x+y)²-(x-y)²
=(x+y+x-y)(x+y-x+y)
=(2x)(2y)
=4xy
=4×(11/25)×(25/22)
=2
1、a^4+a^2b^2+b^4
2、(x+y)²-(x-y)²=4xy=2