①(2y-z)²[2y(z+2y)+z²]²=②(-x-y)²(x²-xy+y²)²=
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![①(2y-z)²[2y(z+2y)+z²]²=②(-x-y)²(x²-xy+y²)²=](/uploads/image/z/531748-28-8.jpg?t=%E2%91%A0%282y-z%29%26%23178%3B%5B2y%28z%2B2y%29%2Bz%26%23178%3B%5D%26%23178%3B%3D%E2%91%A1%EF%BC%88-x-y%29%26%23178%3B%28x%26%23178%3B-xy%2By%26%23178%3B%29%26%23178%3B%3D)
①(2y-z)²[2y(z+2y)+z²]²=②(-x-y)²(x²-xy+y²)²=
①(2y-z)²[2y(z+2y)+z²]²=
②(-x-y)²(x²-xy+y²)²=
①(2y-z)²[2y(z+2y)+z²]²=②(-x-y)²(x²-xy+y²)²=
解①
原式={(2y-z)×[2y(z+2y)+z²]}²
={(2y-z)[(2y)²+2yz+z²]}²
=[(2y)³-z³]²
=(8y³-z³)²
=64y^6-16y³z³+z^6
解②
原式=(x+y)²(x²-xy+y²)²
=[(x+y)(x²-xy+y²)]²
=(x³+y³)²
=x^6+2x³y³+y^6