函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少
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![函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少](/uploads/image/z/615288-48-8.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%3Dsin%282x-%CF%80%2F4%29-2%E6%A0%B9%E5%8F%B72%2Asin%5E2%28x%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E6%98%AF%E5%A4%9A%E5%B0%91)
函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少
函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少
函数f(x)=sin(2x-π/4)-2根号2*sin^2(x)的最小正周期是多少
f(x)=根号2sin2x/2-根号2cos2x/2-2根号2(1-cos2x)/2
=根号2sin2x/2-根号2cos2x/2-根号2+根号2cos2x
=根号2sin2x/2+根号2cos2x/2-根号2
=sin(2x+π/4)-根号2
周期T=2π/w=2π/2=π
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