已知(x+y)²=18,(x-y)²=6,求:①x²+y²的值;②xy的值.
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已知(x+y)²=18,(x-y)²=6,求:①x²+y²的值;②xy的值.
已知(x+y)²=18,(x-y)²=6,求:①x²+y²的值;②xy的值.
已知(x+y)²=18,(x-y)²=6,求:①x²+y²的值;②xy的值.
x²+y²
=[(x+y)²+(x-y)²]/2
=(18+6)/2
=24/2
=12
=12
xy=[(x+y)²-(x-y)²]/4
=(18-6)/4
=12/4
=3
(1)(x+y)²+(x-y)²=24
x²+2xy+y²+x²-2xy+y²=24
2(x²+y²)=24
x²+y²=12
(2)(x+y)²-(x-y)²=12
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(1)(x+y)²+(x-y)²=24
x²+2xy+y²+x²-2xy+y²=24
2(x²+y²)=24
x²+y²=12
(2)(x+y)²-(x-y)²=12
x²+2xy+y²-x²+2xy-y²=12
4xy=12
xy=3
收起
(x+y)^2-(x-y)^2
=x^2+2xy+y^2-(x^2-2xy-y^2)
=4xy=18-6=12
xy=3
x^2+y^2
=(x+y)^2-2xy
=18-2*3
=12