数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
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![数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!](/uploads/image/z/13568757-69-7.jpg?t=%E6%95%B0%E5%AD%A6%E9%A2%98+%E5%85%B3%E4%BA%8Elimit%E5%92%8CContinuity%E7%9A%84+%E6%80%A5%E6%B1%82%21The+function++is+given+by+the+formulawhen++X%26lt%3B1+and+by+the+formulawhen+1%E5%B0%8F%E4%BA%8E%E7%AD%89%E4%BA%8Ex.What+value+must+be+chosen+for++in+order+to+make+this+function+continuous+at+1+%3F%E6%B1%82a%21%E6%80%A5%E6%B1%82+%E8%B0%A2%E8%B0%A2%21)
数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
数学题 关于limit和Continuity的 急求!
The function is given by the formula
when X<1 and by the formula
when 1小于等于x.
What value must be chosen for in order to make this function continuous at 1 ?
求a!
急求 谢谢!
数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
第二个函数式x大于等于1时的形式吧.
求第一个函数在x趋于1(负)时的极限,利用洛贝塔法则,分子就是15x^2-8x+6,这个极限就是等于13.
再求第二个函数在x=1处的函数值,等于9+a,那么
9+a=13
a=4
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数学题 关于limit和Continuity的 急求!The function is given by the formulawhen X<1 and by the formulawhen 1小于等于x.What value must be chosen for in order to make this function continuous at 1 ?求a!急求 谢谢!
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