分组分解法分解因式:2ax-10ay+5by-bx; ab(c^2-d^2)-(a^2-b^2)cd; x^2-y^2+ax+ay连步骤一起给,谢啦,好的话,
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![分组分解法分解因式:2ax-10ay+5by-bx; ab(c^2-d^2)-(a^2-b^2)cd; x^2-y^2+ax+ay连步骤一起给,谢啦,好的话,](/uploads/image/z/2089954-10-4.jpg?t=%E5%88%86%E7%BB%84%E5%88%86%E8%A7%A3%E6%B3%95%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9A2ax-10ay%2B5by-bx%3B+ab%28c%5E2-d%5E2%29-%28a%5E2-b%5E2%29cd%3B+x%5E2-y%5E2%2Bax%2Bay%E8%BF%9E%E6%AD%A5%E9%AA%A4%E4%B8%80%E8%B5%B7%E7%BB%99%2C%E8%B0%A2%E5%95%A6%2C%E5%A5%BD%E7%9A%84%E8%AF%9D%2C)
分组分解法分解因式:2ax-10ay+5by-bx; ab(c^2-d^2)-(a^2-b^2)cd; x^2-y^2+ax+ay连步骤一起给,谢啦,好的话,
分组分解法分解因式:2ax-10ay+5by-bx; ab(c^2-d^2)-(a^2-b^2)cd; x^2-y^2+ax+ay
连步骤一起给,谢啦,好的话,
分组分解法分解因式:2ax-10ay+5by-bx; ab(c^2-d^2)-(a^2-b^2)cd; x^2-y^2+ax+ay连步骤一起给,谢啦,好的话,
2ax-10ay+5by-bx;
=2a(x-5y)-b(x-5y)
=(2a-b)(x-5y)
ab(c^2-d^2)-(a^2-b^2)cd
=abc²-abd²-a²cd+b²cd
=ac(bc-ad)-bd(ad-bc)
=(bc-ad)(ac+bd)
x^2-y^2+ax+ay
=(x-y)(x+y)+a(x+y)
=(x-y+a)(x+y)
2ax-10ay+5by-bx
=(2ax-10ay)-(bx-5by)
=2a(x-5y)-b(x-5y)
=(2a-b)(x-5y)
ab(c^2-d^2)-(a^2-b^2)cd
=abc^2 - abd^2 -a^2 cd + b^2 cd
=(abc^2 + b^2 cd) - ( abd^2 +a^2 cd )
=bc(ac + bd) - ad(bd +ac)
=(ac + bd) (bc - ad)
x^2-y^2+ax+ay
=(x+y)(x-y) +a(x+y)
=(x+y)(x-y+a)
1, =2a(x-5y)-b(x-5y)=(x-5y)(2a-b)
2, =abc²-abd²-a²cd+b²cd=ac(bc-ad)+bd(bc-ad)=(bc-ad)(ac+bd)
3, =(x+y)(x-y)+a(x+y)=(x+y)(x-y+a)