矩形ABCD中,对角线AC、BD交于点O,AE⊥BD于E,若OE=1/3ED,AE=根号3,则BD=?
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![矩形ABCD中,对角线AC、BD交于点O,AE⊥BD于E,若OE=1/3ED,AE=根号3,则BD=?](/uploads/image/z/3579166-46-6.jpg?t=%E7%9F%A9%E5%BD%A2ABCD%E4%B8%AD%2C%E5%AF%B9%E8%A7%92%E7%BA%BFAC%E3%80%81BD%E4%BA%A4%E4%BA%8E%E7%82%B9O%2CAE%E2%8A%A5BD%E4%BA%8EE%2C%E8%8B%A5OE%3D1%2F3ED%2CAE%3D%E6%A0%B9%E5%8F%B73%2C%E5%88%99BD%3D%3F)
矩形ABCD中,对角线AC、BD交于点O,AE⊥BD于E,若OE=1/3ED,AE=根号3,则BD=?
矩形ABCD中,对角线AC、BD交于点O,AE⊥BD于E,若OE=1/3ED,AE=根号3,则BD=?
矩形ABCD中,对角线AC、BD交于点O,AE⊥BD于E,若OE=1/3ED,AE=根号3,则BD=?
设OE=x,则DE=3x,OD=OB=2x=OA,
∴AE=√3x=√3
∴x=1
∴BD=4x=4
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