已知0<α<π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=(tan(α+1/4β)已知0〈α〈 π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=tan(α+1/4β),-1),b=(cosα,2),且a·b=m,求2cosα∧2+sin2(α+β)
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![已知0<α<π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=(tan(α+1/4β)已知0〈α〈 π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=tan(α+1/4β),-1),b=(cosα,2),且a·b=m,求2cosα∧2+sin2(α+β)](/uploads/image/z/3711635-35-5.jpg?t=%E5%B7%B2%E7%9F%A50%EF%BC%9C%CE%B1%EF%BC%9C%CF%80%EF%BC%8F4%2C%CE%B2%E4%B8%BAf%EF%BC%88x%EF%BC%89%3Dcos%EF%BC%882x%2B%CF%80%2F8%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%2C%E5%90%91%E9%87%8Fa%3D%28tan%28%CE%B1%2B1%2F4%CE%B2%29%E5%B7%B2%E7%9F%A50%E3%80%88%CE%B1%E3%80%88+%CF%80%2F4%2C%CE%B2%E4%B8%BAf%EF%BC%88x%EF%BC%89%3Dcos%EF%BC%882x%2B%CF%80%2F8%EF%BC%89%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%2C%E5%90%91%E9%87%8Fa%3Dtan%EF%BC%88%CE%B1%2B1%2F4%CE%B2%EF%BC%89%2C-1%EF%BC%89%2Cb%3D%EF%BC%88cos%CE%B1%2C2%EF%BC%89%2C%E4%B8%94a%C2%B7b%3Dm%2C%E6%B1%822cos%CE%B1%E2%88%A72%2Bsin2%EF%BC%88%CE%B1%2B%CE%B2%EF%BC%89)
已知0<α<π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=(tan(α+1/4β)已知0〈α〈 π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=tan(α+1/4β),-1),b=(cosα,2),且a·b=m,求2cosα∧2+sin2(α+β)
已知0<α<π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=(tan(α+1/4β)
已知0〈α〈 π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=tan(α+1/4β),-1),b=(cosα,2),且a·b=m,求2cosα∧2+sin2(α+β)/cosα-sinα的值
已知0<α<π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=(tan(α+1/4β)已知0〈α〈 π/4,β为f(x)=cos(2x+π/8)的最小正周期,向量a=tan(α+1/4β),-1),b=(cosα,2),且a·b=m,求2cosα∧2+sin2(α+β)
f(x)=cos(2x+π/8)
T=2π/2=π=β
tan(α+β/4)=sin(α+β/4)/cos(α+β/4)
ab=sin(α+β/4)cosα/cos(α+β/4) -2
=(sinα+cosα)cosα/(cosα-sinα) -2
=(sin2α+2cos^2α)/2(cosα-sinα)-2=m
(2cos^2α+sin2α)/(cosα-sinα)=2m+4
[2cos^2α+sin2(α+β)]/(cosα-sinα)
=[2cos^2α+sin(2α+2π)]/(cosα-sinα)
=(2cos^2α+sin2α)/(cosα-sinα)
=2m+4