ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
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![ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd](/uploads/image/z/3947473-1-3.jpg?t=ab%E2%8A%A5ac.ad%E2%8A%A5ae+.ab%3Dac+.ad%3Dae+.%E8%AF%B4%E6%98%8E+be%E2%8A%A5cd)
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
因为ad垂直于ae 所以角DAE等于90° 因为ab垂直于ac 所以角BAC等于90° 角DAE+角GAD=角BAC+角GAD ad=ae ab=ac 三角形BAE全等于三角形CAD ab垂直于ac 所以be垂直于cd
ab⊥ac.ad⊥ae .ab=ac .ad=ae .说明 be⊥cd
如图,AD⊥AE,AB垂直AC,AD=AE,AB=AC,AD⊥AE ,AB=AC,求证:三角形ABD≌三角形ACE
DA⊥AB EA ⊥AC AB=AD AC=AE 求证 DC=BE
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD
如图,AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证BE⊥CD
如图,已知:AB=AE,AC=AD,AC⊥AD,AB⊥AE.求证:ED⊥BC.
如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:BE=DC
已知AD⊥AB,AE⊥AC,AD=AB,AE=AC,求证BE=DC
如图所示,已知AB⊥AC,AD⊥AE,AB=AC,AD=AE,求证:BE=DC非常急
在△ABC中,AD⊥AB,AD=AB,AE⊥AC,AE=AC,求证:BE=CD
如图AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证:△DAC≌三角形EAB
ab=ac AD⊥bd ae⊥ce ad=ae 说明ob=oc
如图,DE//BC,请问AD:AC=AE:AB?AD:AE=AB:AC?
如图.AD⊥AE.AB=AC.BD=CE,问AB与AC的位置关系
如图,直角梯形ABCD,CD‖AB,AB=AC,AE⊥AC,且AE=AD,连BE交AC于F,求证:BF=EF.
如图,直角梯形ABCD,CD‖AB,AB=AC,AE⊥AC,且AE=AD,连BE交AC于F,求证:BF=EF.
如图,AB‖CD,AD‖BC,AE⊥AB,AF⊥AD,AE=AB,AF=AD,试说明AC=EF
如图所示,AD⊥AB,AE⊥AC,且AD=AB,AE=AC.试说明:BE=CD,BE⊥CD