已知,函数f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/20,-π/2
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已知,函数f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/20,-π/2
已知,函数f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/20,-π/2
已知,函数f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/20,-π/2
因为f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/2
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已知,函数f(x)=Acos^2(ωx+φ)+1(A>0,ω>0,-π/20,-π/2
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函数f(x)=Acos(ωx+φ)最小正周期为?