如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF
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![如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF](/uploads/image/z/9934915-67-5.jpg?t=%E5%A6%82%E5%9B%BE%EF%BC%9AAB%3DDC%2CBE%3DDF%2CAF%3DDE.%E6%B1%82%E8%AF%81%EF%BC%9A%E2%96%B3ABE%E5%85%A8%E7%AD%89%E2%96%B3DCF)
如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF
如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF
如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF
AF=DE
AF+EF=DE+EF
AE=DF
AB=DC,BE=DF
△ABE全等△DCF(sss)
AB=DC,BE=DF
△ABE全等△DCF(sss)
题错了,争什么!
这个问题问的够弱智的,这样的问题要是打不上来,我看,楼主也别上学了。
如图,AB=DC,AF=DE,CF=BE,∠AFD=∠DEA.求证:AE‖DF.
如图:AB=DC,BE=DF,AF=DE.求证:△ABE全等△DCF
已知:如图,AB=DC,AE=DF,CE=FB,求证:AF=DE
已知如图AB=DC,AE=DF,CE=FB求证AF=DE
如图,已知AB=DC AE=DF .CE=BF 求证:AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证AF=DE
如图,已知AB=DC,AE=DF,CE=FB,求证:AF=DE
如图,已知AB=DC,AE=DF,CE=BF,求证:AF=DE
如图AB=CD AF平行DF CF平行BE 求证AF=DE
如图AB=CD AF∥DF CF∥BE 求证AF=DE
已知,如图,AB=DC,AF=DE,CF=BE,∠AFD=∠DEA.求证:AE∥DF
如图,AB=DC,BE=CF,AF=DE.求证,BF=CE
如图AB=DC,AD=BC,DE=BF求证BE=DF
如图 已知AD=BC AB=DC DE=BF 求证BE=DF
如图AB=DC,AD=BC,DE=BF求证BE=DF
如图 已知AD=BC AB=DC DE=BF 求证BE=DF
如图,已知:AB=DC,AD=BC,DE=BF.求证:BE=DF.
如图,DE垂直AB,DF垂直AC,DE=DF.求证:AE=AF